有了这个思路,接下来我用了3个循环算法实现了左部分的障碍物设定:
//构建障碍物
for (int y = 12; y <= 27; y++) {
for (int x = 0; x <= 7; x++) {
//障碍物在矩阵中用0表示
Matrix[x, y] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
Carrier.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, y * GridSize);
}
}
int move = 0;
for (int x = 8; x <= 15; x++) {
for (int y = 12; y <= 18; y++) {
Matrix[x, y - move] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
Carrier.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, (y - move) * GridSize);
}
move = x % 2 == 0 ? move + 1 : move;
}
int start_y = 4;
int end_y = 10;
for (int x = 16; x <= 23; x++) {
for (int y = start_y; y <= end_y; y++) {
Matrix[x, y + move] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
Carrier.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, (y + move) * GridSize);
}
start_y = x % 3 == 0 ? start_y + 1 : start_y;
end_y = x % 3 == 0 ? end_y - 1 : end_y;
}