因此，代码：
Vector Strings=new Vector();
Strings.add(“One”);
Strings.add(“Two”);
String Second=(String)Strings.elementAt(1);
可以用如下的代码替换：
StringVector Strings=new StringVector();
Strings.add(“One”);
Strings.add(“Two”);
String Second=Strings.getStringAt(1);
这样就可以通过优化线程来提高JAVA程序的性能。用于测试的程序如下（TestCollection.java）:
import java.util.Vector;
public class TestCollection
{
public static void main(String args [])
{
TestCollection collect = new TestCollection();
if(args.length == 0)
{
System.out.println(
"Usage: java TestCollection [ vector | stringvector ]");
System.exit(1);
}
if(args[0].equals("vector"))
{
Vector store = new Vector();
long start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++)
{
store.addElement("string");
}
long finish = System.currentTimeMillis();
System.out.println((finish-start));
start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++)
{
String result = (String)store.elementAt(i);
}
finish = System.currentTimeMillis();
System.out.println((finish-start));
}
else if(args[0].equals("stringvector"))
{
StringVector store = new StringVector();
long start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++) { store.add("string"); }
long finish = System.currentTimeMillis();
System.out.println((finish-start));
start = System.currentTimeMillis();
for(int i = 0; i < 1000000; i++) {
String result = store.getStringAt(i);
}
finish = System.currentTimeMillis();
System.out.println((finish-start));
}
}
}
/* * * * * * * * * * * * * * * *TestCollection.java * * * * * * * * * * * * * * * * */
测试的结果如下（假设标准的时间为１，越小性能越好）：
