Net Framework: 字符串的驻留（String Interning）-技术开发专区

Net Framework: 字符串的驻留（String Interning）

作者：ITPUB论坛编辑： nancy 2008-03-14 16:49

【IT168技术文档】

关于字符串的驻留的机制，对于那些了解它的人肯定会认为很简单，但是我相信会有很大一部分人对它存在迷惑。在开始关于字符串的驻留之前，先给出一个有趣的Sample：

Code Snip：

static void Main(string[] args)
{
string str1 = "ABCD1234";
string str2 = "ABCD1234";
string str3 = "ABCD";
string str4 = "1234";
string str5 = "ABCD" + "1234";
string str6 = "ABCD" + str4;
string str7 = str3 + str4;
Console.WriteLine("string str1 = \"ABCD1234\";");
Console.WriteLine("string str2 = \"ABCD1234\";");
Console.WriteLine("string str3 = \"ABCD\";");
Console.WriteLine("string str4 = \"1234\";");
Console.WriteLine("string str5 = \"ABCD\" + \"1234\";");
Console.WriteLine("string str6 = \"ABCD\" + str4;");
Console.WriteLine("string str7 = str3 + str4;");
Console.WriteLine("\nobject.ReferenceEquals(str1, str2) = {0}", object.ReferenceEquals(str1, str2));
Console.WriteLine("object.ReferenceEquals(str1,  \"ABCD1234\") = {0}", object.ReferenceEquals(str1, "ABCD1234"));
Console.WriteLine("\nobject.ReferenceEquals(str1, str5) = {0}", object.ReferenceEquals(str1, str5));
Console.WriteLine("object.ReferenceEquals(str1, str6) = {0}", object.ReferenceEquals(str1, str6));
Console.WriteLine("object.ReferenceEquals(str1, str7) = {0}", object.ReferenceEquals(str1, str7));
Console.WriteLine("\nobject.ReferenceEquals(str1, string.Intern(str6)) = {0}", object.ReferenceEquals(str1, string.Intern(str6)));
Console.WriteLine("object.ReferenceEquals(str1, string.Intern(str7)) = {0}", object.ReferenceEquals(str1, string.Intern(str7)));
}

下边是输出的结果：

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